Thursday, 1 December 2011

REF relay setting calculation



REF RELAY SETTING CALCULATION


Transformer Data :

  8 MVA , 6.6KV/ 415 ,  Impedance = 0.0835 p.u., Tap + 10% ( 440Kv – 360KV

CTR = 800 /1

Relay  : CAG 14 / P120

 

                                Fault MVA = MVA  / Transformer Impedance
                                        =  8 / 0.0835 = 95.8084

Fault Current  =    Fault MVA  x 1000 / ( 1.732 x  Voltage rating )
                      =   95.8084 x 1000 ( 1.732 x 6.6 )
                      =    8281.06  Amp primary
                          = 8281.06 / 800  = 10.4763  Amp Secondary

Fault Voltage developed across the relay   =  fault current  x loop resistance
 at the time of Maximum fault conditions

                                    V s       =    If ( Rct + 2 RL)     RL  = CT Lead Resistance
                                                 =   10.4763  x (  Rct + 2 RL)
                                                =    10.4763  x ( 4 + 2)  ( assumed RL = 1 ohms)
                                                =     62.8579 volts
The relay has to be set at   Is = 0.1 In for maximum sensitivity

The stabilizing resistor shall be set at value of resistance during fault minus the relay resistance

                                                =   62.85    -    1 VA
0.1                            (0.1) Square       
                                            = 628.5      -  100
                                                    R     =     528.5 ohms









6 comments:

  1. Dear Mr Bala,
    Have you assumed that the VA of the relay is 1?
    dillipkumarmohanta@gmail.com

    ReplyDelete
  2. Sir,

    Could you please advice me how to calculate the over current and earth fault
    setting?

    ReplyDelete
  3. Sir,

    Could you please advice me how to calculate the over current and earth fault
    setting?

    ReplyDelete